Cache your React event listeners to improve performance.
An in-depth tutorial on how to cache functions
--
An under-appreciated concept in JavaScript is how objects and functions are references, which directly impacts React performance. If you were to create two completely identical functions, they are still not equal. Try for yourself:
But check out the difference if you assign a variable to an already-existing function:
Objects work the same way:
If you have experience in other languages, you may be familiar with pointers. What is happening here is that each time you create an object, you are allocating some amount of memory on the device to it. When I said that object1 = {}, I have created a chunk of bytes in the user’s RAM that is dedicated specifically to object1. It is fair to imagine object1 as an address that contains where in RAM its key-value pairs are located. When I said object2 = {}, I created a different chunk of bytes in the user’s RAM that is dedicated specifically to object2. Does the address of object1 match the address of object2? No. That is why the equality check for the two variables does not pass. Their key-value pairs may be exactly the same, but their addresses in memory are different and that is what is being compared.
When I assigned object3 = object1, I am assigning the value of object3 to be the address of object1. It is not a new object. It is that same location in memory. You can verify this like so:
In this example, I created an object in memory and assigned it to object1. I then assigned object3 to that same address in memory. By mutating object3, I have changed the value at that location in memory, meaning all other references to that location in memory change as well. object1, which still points to that location in memory, now has a changed value.
This is a very common error for junior developers to make and likely warrants an in-depth tutorial of its own, but this particular tutorial is about React performance, which may be compromised even by experienced developers who have simply not considered the implications of variable references.
What does this have to do with React? React has an intelligent way of saving processing time to boost performance: If a component’s props and state have not changed, then the output of render must not have changed either. Clearly, if all things are equal, nothing has changed. If nothing has changed, render must return the same output, so let’s not bother executing it. This is what makes React fast. It only renders as needed.
React determines if its props and state are equal by comparing them with the == operator the same way JavaScript does. React does not use shallow or deep comparison on objects to determine if they are equal. Shallow comparison is a term used to describe comparing each key-value pair of an object, as opposed to comparing the memory address. Deep comparison goes one step further and if any of the values in the key-value pair are also objects, it compares those key-value pairs as well, ad nauseam. React does neither: it merely checks if the references are the same.
If you were to change a component’s prop from { x: 1 } to another object { x: 1 }, React will re-render because those two objects do not reference the same location in memory. If you were to change a component’s prop from object1 (from above) to object3, React would not re-render, because those two objects are the same reference.
In JavaScript, functions are handled the same way. If React receives an identical function with a different memory address, it will re-render. If React receives the same function reference, it will not.
This is an unfortunately common scenario I come across during code review:
This is a pretty straightforward component. There’s a button which alerts when clicked. Instructions tell you whether or not you should click it, which is controlled by the do={true} or do={false} prop of SomeComponent.
What happens here is that every time SomeComponent is re-rendered (such as do toggling from true to false), Button is re-rendered too! The onClick handler, despite being exactly the same, is being created every render call. With each render, a new function is created (because it is created in the render function) in memory, a new reference to a new address in memory is passed to <Button />, and the Button component is re-rendered, despite absolutely nothing having changed in its output.
The Fix
If your function does not depend on your component (no this contexts), you can define it outside of the component. All instances of your component will use the same function reference since the function is identical in all cases.
In contrast to the previous example, createAlertBox remains the same reference to the same location in memory during every render. Button therefore never has to re-render.
While Button is likely a small, quick-to-render component, you may see these inline definitions on large, complex, slow-to-render components, and it can really bog down your React application. It is good practice to simply never define these functions inside the render method.
If your function does depend on your component such that you cannot define it outside the component, you can pass a method of your component as the event handler:
In this case, each instance of SomeComponent has a different alert box. The click event listener for Button needs to be unique to SomeComponent. By passing the createAlertBox method, it does not matter if SomeComponent re-renders. It doesn’t even matter if the message prop changes! The address in memory of createAlertBox does not change, meaning Button does not have to re-render, and you save processing time and improve the rendering speed of your application.
But what if my functions are dynamic?
The Fix (Advanced)
Author’s Note: I wrote the following examples off the top of my head as a way to repeatedly reference the same function in memory. These examples are meant to make comprehension of references easy. While I would recommend reading this section for the purpose of comprehending references, I have included a better implementation at the end that was generously contributed by Chris Ryan via comment. His solution takes into account cache invalidation and React’s built-in memory management.
There is a very common use case that you have a lot of unique, dynamic event listeners in a single component, such as when mapping an array.
In this case, you have a variable number of buttons making a variable number of event listeners, each with a unique function, and you cannot possibly know what is what when creating your SomeComponent. How can you possibly solve this conundrum?
Enter memoization, or what may be easier to refer to as simply, caching. For each unique value, create and cache a function; for all future references to that unique value, return the previously cached function.
This is how I would implement the above example:
Each item in the array is passed through the getClickHandler method. The said method will, the first time it is called with a value, create a function unique to that value then return it. All future calls to that method with that value will not create a new function, instead, it will return the reference to the previously created function in memory.
As a result, re-rendering SomeComponent will not cause Button to re-render. Similarly, adding items to the list prop will create event listeners for each button dynamically.
You may need to use your own cleverness for generating unique identifiers for each handler when they are determined by more than one variable, but it is not much harder than simply generating a unique key prop for each JSX object in the mapped result.
A word of warning for using the index as the identifier: You may get the wrong result if the order of the list changes or items are removed. When your array changes from [ 'soda', 'pizza' ] to just [ 'pizza' ] and you have cached your event listener as listeners[0] = () => alert('soda'), you will find that when you users click the now-index-0 button for pizza that it alerts soda. This is the same reason React advises against using array indices for key props.
A better implementation
Conclusion
If you liked this article, feel free to give it a clap or two. It’s quick, it’s easy, and it’s free! If you have any questions or relevant great advice, please leave them in the comments below.
